Question

A simple pendulum performs S.H.M. about x = 0 with an amplitude a and time period T. What is the speed of the pendulum at x = a/2?

Answer 1

Speed of pendulum, \(v = \omega\sqrt{a^2 \,-\,x^2}\)

\(v=\frac{2\pi}{T}\sqrt{a^2-\frac{a^2}{4}}\)

= \(\frac{\sqrt3a\pi}{T}\)