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Two exactly identical pendulums are oscillating with amplitude 2 cm and 6 cm. Calculate the ratio of their energies of oscillations.

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Total energy of the bob of simple pendulum is given by

E = mω2r2, i.e., E ∝ r2,

So \(\frac{E_1}{E_2}=\frac{r^2_1}{r^2_2}={(\frac{2}{6})}^2=\frac{1}{9}\)

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