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in Vector Algebra by (28.9k points)
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(a) The angle between the vectors \(\bar a\) and \(\bar b\) such that

\(|\vec a| = |\vec b| = \sqrt{2}\)

\(\bar a.\bar b = 1 \)

(i)\(\frac{π}{3}\)

(ii) \(\frac{π}{3}\)

(iii) \(\frac{π}{4}\)

(iv) 0

b) Find the unit vector along \(\bar a - \bar b\) where \(\bar a\) = i + 3j – k and \(\bar b =\) 3i + 2j + k

1 Answer

+1 vote
by (28.2k points)
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Best answer

\(\frac{-2i + j - 2k}{3}\)

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