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Show that the motion of a particle represented by y = sin ωt – cos ωt is simple harmonic with a period of 2π.

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y = sin ωt − cos ωt

= \(\sqrt 2(cos\frac{1}{\sqrt2}sin\, \omega t\,-\,\frac{1}{\sqrt 2}cos\,\omega t)\)

= \(\sqrt 2(cos\frac{\pi}{4}sin\,\omega t\,-\,sin\frac{\pi}{4}cos\,\omega t)\)

∴ y = \(\sqrt 2sin(wt\,-\,\frac{\pi}{4})\)

∴ (sin ωt – cos ωt) represents SHM.

y = \(\sqrt 2sin(\omega t\,-\,\frac{\pi}{4})= \sqrt 2sin(\omega t\,-\,\frac{\pi}{4}\, +2\pi)\) 

= \(\sqrt 2sin(\omega(t+\frac{2\pi}{\omega})\,-\frac{\pi}{4})\) 

∴ Time period = \(\frac{2\pi}{\omega}\)

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