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Prove that the points (3, 0) (6, 4) and (-1, 3) are vertices of a right angled isosceles triangle.

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Let A(3, 0), B (6, 4) and C(-1, 3) be the given points

⇒ AC=√ (16+9)

⇒ AC=√(25)

⇒ AB2=(√25)2

⇒ AB2=25

⇒ AC2=25

⇒ BC2=(√50)2

⇒ BC2=50

Since AB2+AC2=BC2 and AB=AC

∴ ABC is a right angled isosceles triangle

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