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1. Let f be a function defined by f(x) = \(\sqrt{x}\) is a function if it defined from (1)

(a) f : N → N

(b) f : R → R

(c) f : R → R+

(d) f : R+ → R+

2. Check the injectivity and surjectivity of the following functions (3)

(a) f : N → N defined by f(x) = x3

(b) f : R → R given by f(x) = [x]

1 Answer

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Best answer

1.
(d) f : R+ → R+

2.
(a) For x, y ∈ N,

f(x) = f(y) ⇒ x3 = y3 ⇒ x = y

Therefore, f is injective

For 2 ∈ N, there does not exist x in the domain N such that f(x) = x3 = 2.

∴ f is not surjective.

(b) f : R → R given by f(x) = [x]

It seen that f(1.1) = 1 and f(1.8) = 1;

But 1.1 ≠ 1.8;

∴ f is not injective

There does not exist any element x ∈ R

such that f(x) = 0.7

∴ f is not surjective.

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