Sarthaks Test
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On a square handkerchief, nine circular designs each of radius 7 cm are made (see the given figure). Find the area of the remaining portion of the handkerchief.[ Use π = 22/7]

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From the figure, it can be observed that the side of the square is 42 cm.

Area of square = (Side)2 = (42)2 = 1764 cm2

Area of each circle = π r2

  = 22/7 x 7 x 7 = 154 cm2

Area of 9 circles = 9 x 154 = 1386 cm2 

Area of the remaining portion of the handkerchief = 1764 − 1386 = 378 cm2

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