(a) Yes, change of weight will be there,
(b) Given mass = m = 50 kg, v = 2s-1 , A = 5 cm = 0.05 m
Let the platform vibrate between two extreme positions O
P and Q about mean position O.
amax = Maximum acceleration towards mean position O
amax = w2A = (2πv)2 A
= 7.9ms-1
At P, restoring force (mamax) and weight (mg) are directed towards mean position. so net weight at P given by
W1 = mg + mamax = m(g + amax)
= 50(9.8 + 7.9) = 885 N
Similarly, net weight at Q
W2 = mg − mamax = m(g − amax)
= 50(9.8 − 7.9) = 95N
Weight is maximum at top position and minimum at lowermost position.