If there was no cut then the object would have been at a height of 0.5 cm from the principal axis 00’.
Consider the image for this case.
\(\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\)
\(∴ \frac{1}{v}=\frac{1}{u}+\frac{1}{f}=\frac{1}{-50}+\frac{1}{25}=\frac{1}{50}\)
∴ v = 50 cm
Magnification is \(m=\frac{v}{u}=-\frac{50}{50}=-1\).
Thus, the image would have been formed at 50 cm from the pole and 0.5 cm below the principal axis. Hence with respect to the X axis passing through the edge of the cut lens, the co-ordinates of the image are (50 cm, -1 cm)
