Sarthaks Test
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In the given figure, a square OABC is inscribed in a quadrant OPBQ. If OA = 20 cm, find the area of the shaded region. [Use π = 3.14]

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In ΔOAB,

OB2 = OA2 + AB2

= (20)2 + (20)2 

OB = 20√2

Radius (r) of circle = 20√2 cm

Area of quadrant OPBQ

=  90o/360x 3.14 x  (20√2)2

= 1/4 x 3.14 x 800

= 628 cm2

Area of OABC = (Side)2 = (20)2 = 400 cm2

Area of shaded region = Area of quadrant OPBQ − Area of OABC

= (628 − 400) cm2

= 228 cm2

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