Mass of ice eaten by the man per second.
m = \(\frac{100}{60}=\frac{5}{3}\) = \(\frac{5}{3}\) g/m.
Latent heat of ice,
L = 80 cal/g.
Therefore, energy required per second by the man in eating the ice, i.e., power developed by the man,
= mL= \(\frac{5}{3}\) × 80 cal/s
= \(\frac{50\times80}{3}\) × 4.2 J/s = 560 W.