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Calculate the power developed by a person while eating 100 g of ice per minute. (Later heat of ice = 80 cal g-1.)

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Mass of ice eaten by the man per second.

m = \(\frac{100}{60}=\frac{5}{3}\) = \(\frac{5}{3}\) g/m.

Latent heat of ice,

L = 80 cal/g.

Therefore, energy required per second by the man in eating the ice, i.e., power developed by the man,

= mL= \(\frac{5}{3}\) × 80 cal/s

= \(\frac{50\times80}{3}\) × 4.2 J/s = 560 W.

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