Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
5.9k views
in Physics by (30.0k points)

An athlete completes one round of circular track of diameter 200 m in 40 sec. What will be the distance covered and the displacement at the end of 2 minutes 20 sec?

Please log in or register to answer this question.

1 Answer

+1 vote
by (130k points)

Time taken = 2 min 20 sec = 140 sec. 

Radius, r = 100 m. 

In 40 sec the athlete complete one round. 

So, in 140 sec the athlete will complete = 140 ÷ 40 = 3.5 round. 

⇒ Distance covered in 140 sec = 2πr × 3.5 = 2 × 22/7 × 100 × 3.5 = 2200 m. 

At the end of his motion, the athlete will be in the diametrically opposite position. ⇒ Displacement = diameter = 200 m.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...