Sarthaks Test
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Calculate the area of the designed region in the given figure common between the two quadrants of circles of radius 8 cm each.[Use π = 22/7]

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The designed area is the common region between two sectors BAEC and DAFC.

Area of sector BAEC = 90o/360o x 22/7 x (8)2

                                  = 1/4 x 22/7 x 64

                                  = 22/7 x 16

                                  = 352/7 cm2

Area of Δ BAC  = 1/2 x BA x BC

                         = 1/2 x 8 x 8 =32 cm2  

Area of the designed portion = 2 × (Area of segment AEC)

= 2 × (Area of sector BAEC − Area of ΔBAC)

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