Sarthaks Test
0 votes
in Mathematics by (11.0k points)

Calculate the area of the designed region in the given figure common between the two quadrants of circles of radius 8 cm each.[Use π = 22/7]

1 Answer

0 votes
by (18.2k points)
selected by
Best answer

The designed area is the common region between two sectors BAEC and DAFC.

Area of sector BAEC = 90o/360o x 22/7 x (8)2

                                  = 1/4 x 22/7 x 64

                                  = 22/7 x 16

                                  = 352/7 cm2

Area of Δ BAC  = 1/2 x BA x BC

                         = 1/2 x 8 x 8 =32 cm2  

Area of the designed portion = 2 × (Area of segment AEC)

= 2 × (Area of sector BAEC − Area of ΔBAC)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.