Question

Calculate the area of the designed region in the given figure common between the two quadrants of circles of radius 8 cm each.[Use π = 22/7]

Answer 1

The designed area is the common region between two sectors BAEC and DAFC.

Area of sector BAEC = 90^o/360^o x 22/7 x (8)²

                                  = 1/4 x 22/7 x 64

                                  = 22/7 x 16

                                  = 352/7 cm²

Area of Δ BAC  = 1/2 x BA x BC

                         = 1/2 x 8 x 8 =32 cm²  

Area of the designed portion = 2 × (Area of segment AEC)

= 2 × (Area of sector BAEC − Area of ΔBAC)