∴Speed = slope of the graph
Since slope of object B is greater than objects A and C, it is travelling the fastest.
(b) All three objects A, B and C never meet at a single point. Thus, they were never at the same point on road.
(c) On the distance axis:
7 small boxes = 4 km
∴ 1 small box = 4/7 km
Initially, object C is 4 blocks away from the origin.
∴ Initial distance of object C from origin = 16/7 km
Distance of object C from origin when B passes A = 8 km
Distance covered by C = 8 - 16/7 = 65 - 16/7 = 40/7 = 5.715 km
Hence, C has travelled a distance of 5.714 km when B passes A.
(d) Distance covered by B at the time it passes C for 9 boxes = 4/7 x 9 = 36/7 = 5.143 km
Hence, B has travelled a distance of 5.143 km when B passes A.