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in Continuity and Differentiability by (28.9k points)
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Examine the continuity of the function

\(f(x)= \begin{cases} |x|+3,& \quad x≤-3\\ -2x,& \quad -3<x<3\\ 6x + 2,& \quad x≥3 \end{cases} \)

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In the intervals x ≤ -3, f(x) is the sum of a constant function and modulus function so continuous. In the intervals -3 < x < 3 and x ≥ 3the function f(x) is a polynomial so continuous. Hence we have to check the continuity at x = -3, x = 3.

At x = -3

f(-3) = 6

f(x) is continuous at x = -3.
At x = 3
f(3) = 6(3) + 2 = 20

Since limx→3f(x) = f(3), f(x) is not continuous at x = 3.

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