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A ball is gently dropped from a height of 20 m. If its velocity increases uniformly at the rate of 10ms-2 , with what velocity will it strike the ground? After what time will it strike the ground?

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Here, u = 0 m/s, s = 20 m, 

a = 10 ms-2

v = ?, 

t = ? 

Using v 2 – u 2 = 2as 

We have, v 2 – 0 2 = 2 × 10 × 20 = 400 ⇒ v = 20 ms-1

and t = (v – u) ÷ a = 20 ÷ 10 = 2 s.

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