Sarthaks Test
0 votes
103 views
in Mathematics by (11.0k points)

A cubical block of side 7 cm is surmounted by a hemisphere. What is the greatest diameter the hemisphere can have? Find the surface area of the solid.[Use π = 22/7]

1 Answer

0 votes
by (18.2k points)
selected by
 
Best answer

From the figure, it can be observed that the greatest diameter possible for such hemisphere is equal to the cube’s edge, i.e., 7cm.

Radius (r) of hemispherical part = 7/2=3.5

Total surface area of solid = Surface area of cubical part + CSA of hemispherical part − Area of base of hemispherical part

= 6(edge)2 + 2π r2  - π r2

= 6(edge)2 + π r2

Total surface area of solid

=6(7)2 +22/7 x 3.5 x 3.5                                   

= 294 +38.5                                         
 
=332.5cm2

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...