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in Laws of Motion and Friction by (15 points)
edited by

A stone is dropped a height h. It hits the ground with a certain momentum p. If the stone is dropped from a height 100% more than the previous height, the momentum when it hits the ground will change by

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Velocity v= \(\sqrt{2gh}\) .....(i)
and momentum p=mv.....(ii)
From (Eqs.)(i) and (ii), we have

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