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If the momentum of a body is increased by 100 %, then the percentage increase in the kinetic energy is

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If the momentum of a body is increased by 100%, then the percentage increase in the kinetic energy is

A) 150%

B) 200%

C) 225%

D) 300%

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1 Answer

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D) 300%

Explanations:

p = 100% x p + p

 =2p

K'=(p')2/2m

 =4p2/2m

4K=3K +K

=300% K + K

= 300% K+K

KE becomes four times. It means that the kinetic energy increase by 300%.

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