(i) Let P and Q be the point of trisection of AB i.e., AP=PQ=QB
Therefore, P divides AB internally in the ratio of 1:2, thereby applying section formula, the coordinates of P will be
Now, Q also divides AB internally in the ratio of 2:1 there its coordinates are
(ii) Let P, Q be the point of tri section of AB i.e.,
AP=PQ=QB
Therefore, P divides AB internally in the ratio of 1:2
Hence by applying section formula, Coordinates of P are
Now, Q also divides as internally in the ratio of 2:1
So, the coordinates of Q are
(iii) Let P and Q be the points of trisection of AB i.e., AP=PQ=OQ
Therefore, P divides AB internally in the ratio 1 : 2. Therefore, the coordinates of P, by applying the section formula, are
Now, Q also divides AB internally in the ration 2 : 1. So, the coordinates of Q are