Question

Two masses of 5 kg and 3 kg are suspended with the help of massless inextensible strings as shown in Fig. Calculate T₁ and T₂ when whole system is going upward with acceleration = 2 ms² (use g = 9.8 ms^-2).

Answer 1

m₁ = 5 kg, m₂ = 3 kg, g = 9.8 m/s²

Force on mass m₁,

T₁ − T₂ − m₁g = m₁a

T₁ − T₂ − 5g = 5a

T₁ − T₂ = 59.0 N

Force on mass m₂

T₂ − m₂g = m₂a

T₂ = m₂ (g + a)

= 3(9.8+2)

T₂ = 35.4

T₁ = T₂ + 59.0

or T₁ = 35.4 + 59.0

= 94.4 N