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Deduce Graham’s law of diffusion from kinetic theory of gases using expression for pressure.

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Let us consider two gases A and B diffusing into one another. 

Let ρ1 and ρ2 be their densities and v1 and v2 be their respective r.ms. velocities.

Pressure exerted by gas A,

\(P_1= \frac{1}{3}ρ_1V_1^2\) 

and pressure exerted by gas B,

\(P_2= \frac{1}{3}ρ_2v_2^2\)

When steady state of diffusion is reached

P1 = P2

\( \frac{1}{3}ρ_1v_1^2\) \( \frac{1}{3}ρ_2v_2^2\) 

\( \frac{v_1^2}{v_2^2}=\frac{ρ_2}{ρ_1}\)

or \( \frac{v_1}{v_2}=\,\sqrt\frac{ρ_2}{ρ_1}\) 

If r1 and r2 be the rates of diffusion of gases A and respectively.

\(\frac{r_1}{r_2}=\frac{v_1}{v_2}=\sqrt\frac{ρ_2}{ρ_1}\)

Thus this law states that the rate of diffusion of a gas is inversely proportional to the square root of its density.

r ∝ \(\frac{1}{\sqrtρ}\)

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