Sarthaks Test
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Prove that the points (3, -2), (4, 0), (6, -3) and (5, -5) are the vertices of a parallelogram.

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Let P(x,y) be the point of intersection of diagonals AC and 80 of ABCD.

Here mid-point of AC – Mid - point of BD i.e, diagonals AC and BD bisect each other.

We know that diagonals of a parallelogram bisect each other

Therefore ABCD is a parallelogram.

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