0 votes
34.0k views
in Physics by (29.8k points)

Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds.

Please log in or register to answer this question.

1 Answer

0 votes
by (128k points)

Using the equation of motion 

                                                                 s = ut + at 1/ 2 at2 

Distance travelled in 5 s                           s = u × 5 +1/2 a × 52

or s = 5 u + 25/ 2 a ——(i)

Similarly, distance travelled in 4 s, s′ = 4 u + 16/ 2 a——(ii) 

Distance travelled in the interval between 4th and 5th second 

= (s – s′) = (u  +9/2 a) m 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...