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+1 vote
20.9k views
in Physics by (30.0k points)

Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them 

would be in the ratio of u 2/t ; u 2/2 ( Assume upward acceleration is –g and downward acceleration to be +g ).

1 Answer

+1 vote
by (130k points)
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Best answer

We know for upward motion, v2 = u2 – 2 g h or h =  u2 -v2 /2g 

But at highest point v = 0

Therefore, h =  u2 /2

For first ball, h1 = u2 / 2

and for second ball, h2= u2 / 2g

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