Let A(x_{1,}y_{1}), B(x_{2},y_{2}), and C(x_{3},y_{3}) be the vertices of ΔABC.

Let D(1, 1), E(2, -3) and F(3, 4) be the mid-points of sides BC, CA and AB respectively.

Since, D is the mid-point of BC.

Similarly E and F are the mid-points of CA and AB respectively.

From (i), (ii) and (iii) we get

From (i) and (iv) we get

So the coordinates of A are (4,0)

From (ii) and (iv) we get

So the coordinates of B are (2,8)

From (iii) and (iv) we get

So the coordinates of C are (0,-6)

Hence, the vertices of triangle ABC are:

A(4,0), B(2,8) and C(0,-6)