Sarthaks APP
0 votes
4.1k views
in Mathematics by (11.0k points)

A right triangle whose sides are 3 cm and 4 cm (other than hypotenuse) is made to revolve about its hypotenuse. Find the volume and surface area of the double cone so formed. (Choose value of π as found appropriate.)

1 Answer

0 votes
by (18.2k points)
selected by
 
Best answer

The double cone so formed by revolving this right-angled triangle ABC about its hypotenuse is shown in the figure.

Hypotenuse :

 

= √25 =5 cm

Area of ΔABC 1/2 x AB x AC

Volume of double cone = Volume of cone 1 + Volume of cone 2

Surface area of double cone = Surface area of cone 1 + Surface area of cone 2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...