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A right triangle whose sides are 3 cm and 4 cm (other than hypotenuse) is made to revolve about its hypotenuse. Find the volume and surface area of the double cone so formed. (Choose value of π as found appropriate.)

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The double cone so formed by revolving this right-angled triangle ABC about its hypotenuse is shown in the figure.

Hypotenuse :


= √25 =5 cm

Area of ΔABC 1/2 x AB x AC

Volume of double cone = Volume of cone 1 + Volume of cone 2

Surface area of double cone = Surface area of cone 1 + Surface area of cone 2

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