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If the momentum of a body is increased by 100%, then the percentage increase  in the kinetic energy is 

A) 150%

B) 200%

C) 225%

D) 300%

1 Answer

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Best answer

D) 300%

Explanations:

p'=100% x p+p

=2p

K'=(p')/2m

=4p/2m

4K= 3K + K

=300% K + K

KE becomes four times. It means that the kinetic energy increases by 300%.

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