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An oil funnel made of tin sheet consists of a 10 cm long cylindrical portion attached to a frustum of a cone. If the total height is 22 cm, diameter of the cylindrical portion is 8 cm and the diameter of the top of the funnel is 18 cm, find the area of the tin sheet required to make the funnel (see the given figure).

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Radius (r1) of upper circular end of frustum part = 18/2 = 9 cm

Radius (r2) of lower circular end of frustum part = Radius of circular end of cylindrical part = 8/2 = 4 cm

Height (h1) of frustum part = 22 − 10 = 12 cm Height (h2) of cylindrical part = 10 cm

Slant height (l) of frustum part 

Area of tin sheet required = CSA of frustum part + CSA of cylindrical part 

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