Given
n(A) = 21, n(B) = 26, n(C) = 29
n(A ∩ B) = 14, n(C ∩ A) = 12
n(B ∩ C) = 14, n(A ∩ B ∩ C) = 8
(a) n(A ∪ B ∪ C) = n(A) + n(B) + N(C) − n(A ∩ B)
n(B ∩ C) − n(C ∩ A) + n(A ∩ B ∩ C)
= 21 + 26 + 29 – 14 – 12 – 14 + 8
(b) n(C only) = n(C) − n(A ∩ C) − n(B ∩ C) + n(A ∩ B ∩ C)
= 29 – 12 – 14 + 18
= 11