lim(x→π/6)(√3sinx-cosx)/(x-π/6)=?

Question

 \(\lim\limits_{x \to \frac{\pi}{6}}\frac{\sqrt3sinx-cosx}{x-\frac{\pi}{6}}\) = ?

Answer 1

\(\lim\limits_{x \to \frac{\pi}{6}}\frac{\sqrt3sinx-cosx}{x-\frac{\pi}{6}}\)

= \(\lim\limits_{x \to \frac{\pi}{6}}\frac{\sqrt3sinx-cosx}{x-\frac{\pi}{6}}\)

= 2 ∙ 1           

= 2