The number of ways in which 4 novels can be selected from 6 different novels = 6C4 = 15
The number of ways in which 1 dictionary can be selected out of 3 different dictionaries = 3C1 = 3
Now, it is given that dictionary is always in the middle.
Hence, the arrangement look MM D MM
∴ Dictionary is always in the middle as the novels are different, hence they can be arranged in 4! Ways.
Hence, total number of such arrangement = 15 × 3 × 4!
= 15 × 3 × 4 × 3 × 2 × 1
= 1080