The given numbers are 2,5,6,7,9.
The number of different products when 2 or more is taking = the number of ways of taking product of 2 number + number of ways of taking product 3 numbers + number of ways of taking product of 4 number + number of ways taking 5 together
= 5C2 + 5C3 + 5C4 + 5C5
= \(\frac{5!}{3!\space2!}+\frac{5!}{2!\space3!}+\frac{5!}{1!\space4!}+\frac{5!}{0!\space5!}\)
= \(\frac{5.4}{2.1}+\frac{5.4}{2.}+\frac{5}{1}+1\)
= 10 + 10 + 5 + 1
= 26