Perpendicular distance from origin = d = \(\frac{6}{\sqrt{29}}\)
The equation of the Plane is \(\bar r. \hat n\) = d
Cartesian equation is 2x – 3y + 4z = 6
The direction cosines perpendicular to the Plane is
\(\frac{2}{\sqrt{29}}\), \(-\frac{3}{29}\), \(\frac{4}{29}\).
Perpendicular distance to the Plane is as \(\frac{6}{\sqrt{29}}\)
Hence the foot of the perpendicular is