1. By putting λ = 0 in line L1 and µ = 0 in L2 we get the required points. L1 ⇒ \(\bar r\) = 3i + 4j – 2k
∴ Co-ordinate is (3, 4, -2)
L2 ⇒ \(\bar r\) = i – 7j – 2k
∴ Co-ordinate is (1, -7, -2).
2. Distance between (3, 4, -2) and (1, -7, -2)
3. Let L1 ⇒ \(\bar r\) = 3i + 4j – 2k + λ(-i + 2j + k) is of the form \(\bar r\) = \(\bar a_1\) +λ\(\bar b_1\) where