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in Three Dimensional Geometry by (28.2k points)
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Consider the pair of lines \(\bar r\) = 3i + 4j – 2k + λ(-i + 2j + k) \(\bar L_1\)\(\bar r\) = i – 7j – 2k + µ(i + 3j + 2k) \(\bar L_2\)

  1. Find one point each on lines L1 and L2
  2. Find the distance between those points. 
  3. Find the shortest distance between L1 and L2.

1 Answer

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by (28.9k points)
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Best answer

1. By putting λ = 0 in line L1 and µ = 0 in L2 we get the required points. L1 ⇒ \(\bar r\) = 3i + 4j – 2k

∴ Co-ordinate is (3, 4, -2)
L2 ⇒ \(\bar r\) = i – 7j – 2k
∴ Co-ordinate is (1, -7, -2).

2. Distance between (3, 4, -2) and (1, -7, -2)

3. Let L1 ⇒ \(\bar r\) = 3i + 4j – 2k + λ(-i + 2j + k) is of the form \(\bar r\)\(\bar a_1\)\(\bar b_1\) where

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