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Find n,if \(\lim\limits_{n \to 2}\frac{x^n-2^n}{x-2}=80\), n ∈ N.

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Given,
\(\lim\limits_{n \to2}\frac{x^n-2^n}{x-2}=80\)

⇒ \(n.2^{n-1}=80\)

n2 = 52

\([∵ \lim\limits_{n \to a}\frac{x^n-a^n}{x-a}=na^{n-1}]\)

∵ Value of n is 5.

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