Describe the events as follows
E: ‘getting an easy question.’
F: ‘getting a multiple choice question.’
Total Questions = 300 + 200 + 500 + 400 = 1400
n(F) = 500 + 400 = 900, n(E ∩ F) = 500
\(P(F) = \frac{900}{1400} = \frac{9}{14},\) P(E ∩ F) = \(\frac{500}{1400}\) = \(\frac{5}{14}\)
Therefore the required probability
P(E/F) = \(\frac{P(E \cap F)}{P(F)} = \frac{\frac{5}{14}}{\frac{9}{14}} = \frac{5}{9}\).