Let A(x1,y1), B(x2,y2), C(x3,y3) vertices of ΔABC
Let D(3, -2), E(-3, 1) and F(4, -3) be the midpoint of sides , BCCAand AB respectively
Since, D is the midpoint of BC
Similarly, E and F are the midpoint of CA and AB respectively.
From (i), (ii) and (iii), we have
So, the coordinates of A are (-2,0)
From (ii) and (iv)
So, the coordinates of B are (10,-6)
From (iii) and (iv)
So, the coordinates of C are (-4,2)
Hence, the vertices of ΔABC are A(-2,0), B(10,6) and C(-4,2)