Question

A particle executes S.H.M with amplitude 0.2 m and time period is 24 s. The time required for it to move from the mean position to a point 0.1 m is 

A) 2 s 

B) 3 s 

C) 8 s 

D) 12 s

Answer 1

A) 2 s

Explanations:

Amplitude of particle executing SHM 0.2m. Time period T=24s

Hence

\(x=0.2\sin\omega t\)

\(\sin\omega t =\frac{1}{2}=sin\frac{\pi}{6}\)

\(\frac{2\pi}{24}t=\frac{\pi}{6}\)

\(\implies t=2s\)