Given, inclination of the line, θ = 30°.
Slope of the line, m = tan 30°
= \(\frac{1}{\sqrt{3}}\)
Equation of a line in one-point form is
y – y0 = m(x – x0)
Since m = \(\frac{1}{\sqrt{3}}\) and (x0, y0) = (2, 3)
∴ y − 3 = \(\frac{1}{\sqrt{3}}\)(x − 2)
⇒ \(\sqrt{3}\)y − 3\(\sqrt{3}\) = x – 2
⇒ x − \(\sqrt{3}\)y + (2 − 3\(\sqrt{3}\)) = 0, is the required equation of the line.