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Reduce the equation 6x + 2y + 5 = 1 into intercept form and find its intercepts on the axes.

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Best answer

The given equation is

6x + 2y + 5 = 0

Here, A = 6, B = 2, C = 5

Equation in intercept form is

\(\frac{x}{-\frac{C}{A}} + \frac{y}{-\frac{C}{B}}\) = 1

\(\frac{x}{-\frac{5}{6}} + \frac{y}{-\frac{2}{6}}\) = 1

\(\frac{x}{-\frac{5}{6}} + \frac{y}{-\frac{2}{6}}\) = 1,

\(\frac{x}{-\frac{5}{6}} + \frac{y}{-\frac{1}{3}}\) = 1, where a (intercept on x-axis)

= − \(\frac{5}{6}\) and b (intercept on y – axis) = − \(\frac{1}{3}\)

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