Given line is x + 4y – 5 = 0
Here, A = 1, B = 4, C = – 5 and the given point is (x1, y1) = (2, 3)
∴ Distance, d = \(\bigg|\frac{A_1 x + B_1 y + C_1}{\sqrt{A^2 + B^2}}\bigg|\)
= \(\bigg|\frac{1.2 + 4.3 + 5}{\sqrt{1^2 + 4^2}}\bigg|\)
= \(\frac{9}{\sqrt{17}}\)
= \(\frac{9\sqrt{17}}{17}\) units