Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.0k views
in Statistics by (36.2k points)
closed by

Find the standard deviation of first ‘ten’ natural numbers.

1 Answer

+1 vote
by (33.4k points)
selected by
 
Best answer

Here, 

The variable are 1,2, 3,…,9,10

n = 10

∴ Standard deviation,

\(σ=\sqrt\frac{\sum_{i=1}^{10} x_i^2}{10}\)-\((\frac{\sum_{i=1}^{10} x_i}{10})^2\)

=\(\sqrt\frac{1}{10}.\frac{10(10+1)(20+1)}{6}-\)\((\frac{10(10+1)}{2.10})^2\)

=\(\sqrt\frac{11.21}{6}-(\frac{11}{2})^2\)

=\(\sqrt\frac{77}{2}-\frac{121}{4}\)

\(\frac{1}{2}\sqrt {154-121}\)

\(\frac{1}{2}\sqrt {33}\)

= 2.83.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...