Let ‘a’ be the acute angle made by the line with positive x-axis.
∴ Equation of the line is x cos a + y sin a = 3 …(1)
Since the line passes through (– 5, 0), so
⇒ – 5 cos a + 0. Sin a = 3
⇒ cos a = – \(\frac{3}{5}\)
⇒ sin a = \(\sqrt{1 − (-\frac{3}{5})^2}\) = \(\sqrt{1 − \frac{9}{25}}\) = \(\frac{4}{5}\)
(1) ⇒ x(− \(\frac{3}{5}\)) + y(\(\frac{4}{3}\)) = 3
⇒ 3x – 4y + 15 = 0, is the required of line.