Given, f (x), = x and g (x) = |x| be two real valued functions’
(f + g)(x) = f(x) + g (x) = x + |x| =\(\begin{cases}
2x, & \quad x\geq 0\\
0 & \quad x<0
\end{cases}\)
For x= 2 – h, f (x) = x2 – 1
∴ f (2 – h) = (2 – h)2 – 1
= 4 + h2 – 4h – 1
= 3 + h2 – 4h
For x = – 1 + h, f(x) = 1 + x
∴ f(– 1 + h) = 1 + (– 1 + h)
= h