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Find the equation of the line which is equidistant from the parallel lines 9x + 6y – 7 = 0 and 3x + 2y + 6 = 0.

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The given parallel lines are 

9x + 6y – 7 = 0    …(1) 

3x + 2y + 6 = 0. 

⇒ 9x + 6y + 18 = 0   …(2)  

Let the line which is equidistant from (1) and (2) be 9x + 6y + \(\lambda\)= 0   …(3) 

Distance between (1) and (2) = \(^\frac{|7 - \lambda|}{\sqrt{9^2+6^2}}\) = \(^\frac{|7+ \lambda|}{\sqrt{117}}\)

and distance between (2) and (3) = \(^\frac{|18 - \lambda|}{\sqrt{9^2+6^2}}\)=\(^\frac{|18 - \lambda|}{\sqrt{117}}\)

Given,

\(^\frac{|7+ \lambda|}{\sqrt{117}}\)=\(^\frac{|18 - \lambda|}{\sqrt{117}}\)

⇒ 7 + \(\lambda\) = 18 – \(\lambda\)\(\lambda\) = \(\frac{11}{2}\)

The equation of the required line is 

9x + 6y +\(\frac{11}{2}\) = 0

⇒ 18x + 12y + 11 = 0

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