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Show that the points A(1, 0), B( 5, 3), C( 2, 7) and D(-2, 4) are the vertices of a parallelogram.

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Let A(1, 0), B( 5, 3), C( 2, 7) and D(-2, 4) be the given points

Coordinates of the midpoint of AC are 

Coordinates of the midpoint of BD are 

Since, coordinates of midpoint of AC = coordinates off midpoint of BD

Therefore, ABCD is a parallelogram as we know diagonals of parallelogram bisect each other.

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