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If each diode in Fig. 14.13 has a forward bias resistance of 25Ω and infinite resistance in reverse bias, what will be the values of the current I1, I2, I3 and I4?

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I3 is zero as the diode in that branch is reverse bised. Resistance in the branch AB and EF are each (125 + 25)Ω = 150Ω.

As AB and EF are identical parallel branches, their effective resistance is 150/2=75Ω

Net resistance in the circuit = (75 + 25) Ω = 100Ω .

Current I1=5/100=0.05A.

As resistances of AB and EF are equal, and I1 = I2 + I3 + I4, I3 = 0

I2=I4=0.05/2=0.025A

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